0=4.9t^2/10+9t/10+11/5

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Solution for 0=4.9t^2/10+9t/10+11/5 equation: 


t in (-oo:+oo)

0 = (4.9*t^2)/10+(9*t)/10+11/5 // - (4.9*t^2)/10+(9*t)/10+11/5

0-((4.9*t^2)/10)-((9*t)/10)-(11/5) = 0

(-9/10)*t-0.49*t^2-11/5 = 0

-0.49*t^2-9/10*t-11/5 = 0

DELTA = (-9/10)^2-(-11/5*(-0.49)*4)

DELTA = -3.502

DELTA < 0

t belongs to the empty set

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